Programming in Java | NPTEL 2022 | Week 1 Assignments Solutions

This article will help you with the solutions of the Programming in Java NPTEL 2022 Week 1 Assignment.

Programming in Java NPTEL Week 1 Assignment 1 Solutions

Complete the code segment to find the perimeter and area of a circle given a value of radius.

You should use Math.PI constant in your program. If radius is zero or less than zero then print ” please enter non zero positive number “.

import java.util.Scanner;  
public class Exercise1_1 {
       public static void main(String[] args) {
Scanner s = new Scanner(System.in); 
       double radius= s.nextDouble();
       double perimeter;
       double area;

//Calculate the perimeter 
  //Calculate the area

perimeter = 2 * Math.PI * radius;
area = Math.PI * radius * radius;

System.out.println(perimeter);
System.out.print(area);

  }
}

Note: If you use System.out.println(area) then your code will run but a small error will be faced i.e.,

Passed after ignoring Presentation Error

In order to run the code 100% correct you have to use print instead of println.

Week 1: Programming Assignment 2 Solution

Programming in Java NPTEL Week 1 assignment solutions

Complete the code segment to find the largest among three numbers x, y, and z. You should use if-then-else construct in Java.

import java.util.Scanner;  
public class Exercise1_2 {
       public static void main(String[] args) {
Scanner s = new Scanner(System.in); 
        int x = s.nextInt(); 
        int y = s.nextInt();
int z = s.nextInt();
int result = 0;

//Use if...else ladder to find the largest among 3 numbers and store the largest number in a variable called result.

if(x > y && x > z) {
   result = x;
}
else if(y > x && y > z) {
   result = y;
}
else {
   result = z;
}
System.out.print(result);

  }
}

Week 1: Programming Assignment 3 Solution

Consider First n even numbers starting from zero(0).Complete the code segment to calculate sum of  all the numbers divisible by 3 from 0 to n. Print the sum.
Example:
Input: n = 5
——-
0 2 4 6 8
Even number divisible by 3:0 6
sum:6

import java.util.Scanner;
public class Exercise1_3 {
       public static void main(String[] args) {
	   Scanner sc = new Scanner(System.in);
	   int n=sc.nextInt();
	  int sum=0;

//Use for or while loop do the operation.

for(int i = 0; i < n; i += 2) {
    if(i % 3 == 0) {
        sum = sum + i;
    }
}
System.out.print(sum);

  }
}

Week 1: Programming Assignment 4 Solution

Complete the code segment to check whether the number is an Armstrong number or not.

Armstrong Number:
A positive number is called an Armstrong number if it is equal to the sum of cubes of its digits for example 153 = 1³+5³+3³, 370, 371, 407, etc.

import java.util.Scanner;
public class Exercise1_4 {
    public static void main(String[] args) {
	   Scanner sc = new Scanner(System.in);
	   int n=sc.nextInt();
           int result=0;

//Use while loop check the number is Armstrong or not.
//store the output(1 or 0) in result variable.
  
int actual_number = n;
int number = 0;
while(n!=0) {
  int digit = n%10;
  number += (digit * digit * digit);
  n = n/10;
}

// if number is palindrome
if(number==actual_number){
  result = 1;
}

System.out.print(result);

  }
}

Week 1: Programming Assignment 5 Solution

Complete the code segment to help Ragav , find the highest mark and average mark secured by him in “s” number of subjects.

import java.util.Scanner;
public class Exercise1_5{
    public static void main(String[] args) {
	 Scanner input = new Scanner(System.in);
         double mark_avg;
         int result;
         int i;
         int s;
      //define size of array
       s = input.nextInt();
     //The array is defined "arr" and inserted marks into it.
      int[] arr = new int[s];   
      for(i=0;i<arr.length;i++)
	  {
	arr[i]=input.nextInt();
        }

//Initialize maximum element as first element of the array.  
   //Traverse array elements to get the current max.
   //Store the highest mark in the variable result.
   //Store average mark in avgMarks.

int max = arr[0];
int sum = 0;
for(i=0; i<arr.length; i++){
  sum += arr[i];
  if(arr[i]>max){
    max = arr[i];
  }
}
double average_marks = sum/arr.length;
System.out.println(max);
System.out.print(average_marks);

  }
}

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